For a prism with a refractive index of $1.5$,what is the prism angle $A$ if the angle of minimum deviation is equal to the prism angle (in $^\circ$)? (Given: $\cos 41^\circ = 0.75$)

The angle of a prism is $60^o$ and its refractive index is $\sqrt{2}$. The angle of minimum deviation suffered by a ray of light in passing through it is......$^o$

Yellow light is refracted through a prism producing minimum deviation. If $i_1$ and $i_2$ denote the angle of incidence and emergence for the prism,then ..........

$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a prism of small angle '$A$' and emerges normally from the other surface. If the refractive index of the material of the prism is '$\mu$',then the angle of incidence is equal to

$A$ prism of refractive index $\sqrt{2}$ has a refracting angle of $60^{\circ}$. In order for a ray to suffer minimum deviation,it should be incident at an angle of .......$^{\circ}$.

$A$ ray of monochromatic light is passing through an equilateral prism $(ABC)$ as shown in the figure. The refracted ray $(QR)$ is parallel to its base $(BC)$ and the angle of incidence $(i)$ is $50^\circ$. Then the angle of deviation $(\delta)$ is: (in $^\circ$)