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(A) According to Faraday's law of electrolysis, the mass $m$ deposited is given by $m = ZIt$, where $Z$ is the electrochemical equivalent, $I$ is the

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$+ 0.04$

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(A) According to Faraday's law of electrolysis, the mass $m$ deposited is given by $m = ZIt$, where $Z$ is the electrochemical equivalent, $I$ is the actual current, and $t$ is the time in seconds.Given: $m = 2.0124 \ g$, $Z = 1.118 	imes 10^{-3} \ g \ C^{-1}$, $t = 1 \ hour = 3600 \ s$.The actual current $I$ is calculated as:$I = \frac{m}{Zt} = \frac{2.0124}{1.118 	imes 10^{-3} 	imes 3600}$$I = \frac{2.0124}{4.0248} = 0.5 \ A$.The ammeter reading is $I_{obs} = 0.54 \ A$.The error in the ammeter reading is defined as $I_{obs} - I_{actual}$.Error $= 0.54 \ A - 0.5 \ A = +0.04 \ A$.

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