The temperature of the hot junction of a ther | vedclass

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Question

(D) The thermoelectric power $P$ is directly proportional to the temperature difference $	heta$ between the junctions, i.e., $P \propto 	heta$.Given

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$25$

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(D) The thermoelectric power $P$ is directly proportional to the temperature difference $	heta$ between the junctions, i.e., $P \propto 	heta$.Given, initial temperature $	heta_1 = 80\,\,^{\circ}	ext{C}$ and final temperature $	heta_2 = 100\,\,^{\circ}	ext{C}$.The percentage change in thermoelectric power is given by:$	ext{Percentage Change} = \frac{P_2 - P_1}{P_1} 	imes 100$Since $P \propto 	heta$, we can write:$	ext{Percentage Change} = \frac{	heta_2 - 	heta_1}{	heta_1} 	imes 100$Substituting the values:$	ext{Percentage Change} = \frac{100 - 80}{80} 	imes 100$$	ext{Percentage Change} = \frac{20}{80} 	imes 100$$	ext{Percentage Change} = \frac{1}{4} 	imes 100 = 25\,\%$.

The temperature of the hot junction of a thermocouple is increased from $80\,\,^{\circ}\text{C}$ to $100\,\,^{\circ}\text{C}$. The percentage change in the thermoelectric power will be ............ $\%$.

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