A current of 5,A flows through a resistance o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Current $I = 5\,A$, Resistance $R = 10\, \Omega$, Time $t = 4\, 	ext{minutes} = 4 	imes 60 = 240\,s$.First, calculate the total charge $Q

Vedclass · Accepted Answer

$75 	imes 10^{20}, 1200\ C$

Vedclass · Answer

(C) Given: Current $I = 5\,A$, Resistance $R = 10\, \Omega$, Time $t = 4\, 	ext{minutes} = 4 	imes 60 = 240\,s$.First, calculate the total charge $Q$ using the formula $Q = I 	imes t$:$Q = 5\,A 	imes 240\,s = 1200\,C$.Next, calculate the number of electrons $n$ using the quantization of charge formula $Q = n 	imes e$, where $e = 1.6 	imes 10^{-19}\,C$:$n = \frac{Q}{e} = \frac{1200}{1.6 	imes 10^{-19}} = \frac{12000}{1.6} 	imes 10^{18} = 7500 	imes 10^{18} = 75 	imes 10^{20}$.Thus, the number of electrons is $75 	imes 10^{20}$ and the charge is $1200\,C$.

$A$ current of $5\,A$ flows through a resistance of $10\, \Omega$ for $4$ minutes. The total charge in Coulombs and the number of electrons passing through any cross-section of the resistor in this time are, respectively:

Similar Questions

Define $1 \ Coulomb$ in terms of $1 \ Ampere$.

In a conductor,$4$ coulombs of charge flows for $2$ seconds. The value of electric current will be:

The quantity of charge that will be transferred by a current flow of $20 \text{ A}$ over a period of $1 \text{ hour } 30 \text{ minutes}$ is:

Write the direction of the electric current between the electrodes of an electric cell.

An electron revolves $6 \times 10^{15}$ times per second in a circular loop. The current in the loop is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module