(D) The potential difference $V$ across the resistor is given by $V = x \cdot l$,where $x$ is the potential gradient and $l$ is the balancing length.G

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(D) The potential difference $V$ across the resistor is given by $V = x \cdot l$,where $x$ is the potential gradient and $l$ is the balancing length.Given: $x = 2 \, mV/cm = 2 \times 10^{-3} \, V/cm$,$l = 50 \, cm$,and $R = 10 \, \Omega$.Calculating the potential difference: $V = (2 \times 10^{-3} \, V/cm) \times 50 \, cm = 100 \times 10^{-3} \, V = 0.1 \, V$.Using Ohm's law,$V = iR$,the current $i$ is $i = V / R$.$i = 0.1 \, V / 10 \, \Omega = 0.01 \, A$.Converting to milliamperes: $i = 0.01 \times 1000 \, mA = 10 \, mA$.

Class 12 Physics Current Electricity Potentiometer

Difficult

$A$ potentiometer has a potential gradient of $2 \, mV/cm$. It is used to measure the potential difference across a $10 \, \Omega$ resistor. If the length of the potentiometer wire required to obtain the null point is $50 \, cm$,the current flowing through the $10 \, \Omega$ resistor is ............. $mA$.

A
$1$
B
$2$
C
$5$
D
$10$

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Current Electricity

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Potentiometer

Two cells $A$ and $B$ are connected in the secondary circuit of a potentiometer one at a time and the balancing lengths are respectively $360 \ cm$ and $420 \ cm$. If the emf of $A$ is $2.4 \ V$,the emf of the second cell $B$ is (in $V$)

EasyAP EAMCET 2022

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Potentiometer measures the potential difference more accurately than a voltmeter because

MediumMHT CET 2007

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The balancing length for a cell is $560 \; cm$ in a potentiometer experiment. When an external resistance of $10 \; \Omega$ is connected in parallel to the cell,the balancing length changes by $60 \; cm$. If the internal resistance of the cell is $\frac{N}{10} \; \Omega$,where $N$ is an integer,then the value of $N$ is:

MediumJEE MAIN 2020

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The $e.m.f.$ of a standard cell balances across $150 \ cm$ length of a potentiometer wire. When a resistance of $2 \ \Omega$ is connected as a shunt across the cell,the balance point is obtained at $100 \ cm$. The internal resistance of the cell is .............. $\Omega$.

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$A$ $10 \, m$ long wire of $20 \, \Omega$ resistance is connected with a battery of $3 \, V$ $e.m.f.$ (negligible internal resistance) and a $10 \, \Omega$ resistance is joined to it in series. The potential gradient along the wire in $V/m$ is:

Medium

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Two cells $A$ and $B$ are connected in the secondary circuit of a potentiometer one at a time and the balancing lengths are respectively $360 \ cm$ and $420 \ cm$. If the emf of $A$ is $2.4 \ V$,the emf of the second cell $B$ is (in $V$)

Potentiometer measures the potential difference more accurately than a voltmeter because

The $e.m.f.$ of a standard cell balances across $150 \ cm$ length of a potentiometer wire. When a resistance of $2 \ \Omega$ is connected as a shunt across the cell,the balance point is obtained at $100 \ cm$. The internal resistance of the cell is .............. $\Omega$.

$A$ $10 \, m$ long wire of $20 \, \Omega$ resistance is connected with a battery of $3 \, V$ $e.m.f.$ (negligible internal resistance) and a $10 \, \Omega$ resistance is joined to it in series. The potential gradient along the wire in $V/m$ is:

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