The current passing through a copper voltamet | vedclass

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(D) The charge flowing per minute is given by $Q = I 	imes t$.Given $I = 3.2 \ A$ and $t = 60 \ s$,we have $Q = 3.2 	imes 60 = 192 \ C$.Each copper

Vedclass · Accepted Answer

$6 	imes 10^{20}$

Vedclass · Answer

(D) The charge flowing per minute is given by $Q = I 	imes t$.Given $I = 3.2 \ A$ and $t = 60 \ s$,we have $Q = 3.2 	imes 60 = 192 \ C$.Each copper ion $(Cu^{2+})$ requires $2$ electrons to be deposited at the cathode.The charge of one electron is $e = 1.6 	imes 10^{-19} \ C$.Therefore,the charge required per ion is $2e = 2 	imes 1.6 	imes 10^{-19} = 3.2 	imes 10^{-19} \ C$.The number of ions $n$ deposited is $n = \frac{Q}{2e}$.$n = \frac{192}{3.2 	imes 10^{-19}} = 60 	imes 10^{19} = 6 	imes 10^{20}$ ions.

The current passing through a copper voltameter is $3.2 \ A$. The number of copper ions $(Cu^{2+})$ deposited at the cathode per minute is:

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