The galvanometer shows no deflection. What is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The circuit is a balanced Wheatstone bridge because the galvanometer shows no deflection.Let $R_1$ be the equivalent resistance of the parallel co

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(C) The circuit is a balanced Wheatstone bridge because the galvanometer shows no deflection.Let $R_1$ be the equivalent resistance of the parallel combination of $x \ \Omega$ and $6 \ \Omega$,and $R_2 = 2 \ \Omega$.Let $R_3 = 6 \ \Omega$ and $R_4 = 3 \ \Omega$.For a balanced bridge,the condition is $\frac{R_1}{R_2} = \frac{R_3}{R_4}$.Here,$R_1 = \frac{x \cdot 6}{x + 6}$.Substituting the values: $\frac{\frac{6x}{x+6}}{2} = \frac{6}{3}$.$\frac{6x}{2(x+6)} = 2$.$\frac{3x}{x+6} = 2$.$3x = 2x + 12$.$x = 12 \ \Omega$.

The galvanometer shows no deflection. What is the value of the resistance $x$ in $\Omega$?

Similar Questions

Five equal resistances each of value $R$ are connected in a form shown alongside. The equivalent resistance of the network

In the given circuit,the current through $AB$ is zero. What will be the value of the unknown resistance $X$ in $\Omega$?

The current flowing through the circuit shown in the figure is ............ $A$.

For the circuit shown,with $R_1 = 1.0\,\Omega$,$R_2 = 2.0\,\Omega$,$E_1 = 2\,V$ and $E_2 = E_3 = 4\,V$,the potential difference between the points $a$ and $b$ is approximately (in $V$):

In a Wheatstone network,$P=2 \Omega, Q=2 \Omega, R=2 \Omega$,and $S=3 \Omega$. The resistance with which $S$ is to be shunted so that the bridge may be balanced is: (in $\Omega$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module