If a current of 8 A flows through a heater w | vedclass

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(B) The formula for electric current is $I = \frac{q}{t} = \frac{Ne}{t}$,where $I$ is the current,$N$ is the number of electrons,$e$ is the elementary

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$3 	imes 10^{21}$ electrons

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(B) The formula for electric current is $I = \frac{q}{t} = \frac{Ne}{t}$,where $I$ is the current,$N$ is the number of electrons,$e$ is the elementary charge,and $t$ is the time.Given: $I = 8 \ A$,$t = 1 \ 	ext{minute} = 60 \ s$,and $e = 1.6 	imes 10^{-19} \ C$.Rearranging the formula to solve for $N$: $N = \frac{I 	imes t}{e}$.Substituting the values: $N = \frac{8 	imes 60}{1.6 	imes 10^{-19}}$.$N = \frac{480}{1.6 	imes 10^{-19}} = 300 	imes 10^{19} = 3 	imes 10^{21}$ electrons.

If a current of $8 \ A$ flows through a heater wire,what is the number of electrons passing through it in one minute?

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