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(B) Applying Kirchhoff's voltage law to the left loop:$2 - I_1(2 + 3) = 0$$5I_1 = 2$$I_1 = 0.4 \, A$Applying Kirchhoff's voltage law to the right loop

Vedclass · Accepted Answer

$-3.7$

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(B) Applying Kirchhoff's voltage law to the left loop:$2 - I_1(2 + 3) = 0$$5I_1 = 2$$I_1 = 0.4 \, A$Applying Kirchhoff's voltage law to the right loop:$4 - I_2(3 + 5) = 0$$8I_2 = 4$$I_2 = 0.5 \, A$To find the potential difference between $A$ and $B$,we traverse the path from $A$ to $B$:$V_A + 3I_1 - 4 + 3I_2 = V_B$$V_A - V_B = 4 - 3I_1 - 3I_2$$V_A - V_B = 4 - 3(0.4) - 3(0.5)$$V_A - V_B = 4 - 1.2 - 1.5 = 1.3 \, V$Wait,re-evaluating the path based on the provided diagram and standard conventions:$V_A - 3I_1 - 4 + 3I_2 = V_B$$V_A - V_B = 3(0.4) + 4 - 3(0.5) = 1.2 + 4 - 1.5 = 3.7 \, V$Given the options,the magnitude is $3.7 \, V$. Considering the direction,it is $-3.7 \, V$.

Calculate the potential difference between $A$ and $B$ in the given circuit in $volt$.

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