If the Wheatstone bridge shown in the figure | vedclass

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(D) For a balanced Wheatstone bridge,the ratio of resistances in opposite arms must be equal,i.e.,$\frac{P}{Q} = \frac{R}{S}$.Looking at the outer loo

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$3$,any value

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(D) For a balanced Wheatstone bridge,the ratio of resistances in opposite arms must be equal,i.e.,$\frac{P}{Q} = \frac{R}{S}$.Looking at the outer loop,the bridge is balanced if $\frac{10}{R_1} = \frac{30}{9}$.Solving for $R_1$: $R_1 = \frac{10 	imes 9}{30} = 3 \ \Omega$.In a balanced Wheatstone bridge,the potential difference across the central galvanometer arm (containing $R_2$) is zero. Therefore,no current flows through the branch containing $R_2$. Consequently,the value of $R_2$ does not affect the balance condition and can be any value.

If the Wheatstone bridge shown in the figure is balanced,then the values of $R_1$ and $R_2$ are ...... $\Omega$ and ...... $\Omega$ respectively.

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