An electric heater and an electric bulb are rated $500\, W, 220\, V$ and $100\, W, 220\, V$ respectively. Both are connected in series to a $220\, V$ $a.c.$ mains. The power consumed by the heater and the bulb respectively is:

Assertion : In a simple battery circuit,the point of the lowest potential is the negative terminal of the battery.
Reason : The current flows towards the point of the higher potential,as it does in such a circuit from the negative to the positive terminal.

Two resistances of $400 \Omega$ and $800 \Omega$ are connected in series with a $6 \text{ V}$ battery of negligible internal resistance. $A$ voltmeter of resistance $10000 \Omega$ is used to measure the potential difference across the $400 \Omega$ resistor. The error in the measurement of potential difference in volts is approximately:

In the given circuit,if the current through the $10 \Omega$ resistor is $2.5 \text{ A}$,the value of $R$ is . . . . . . . (in $\Omega$)

In the given circuit,the resistance of the voltmeter is $10,000\, \Omega$ and the resistance of the ammeter is $20\, \Omega$. The ammeter reading is $0.1\, \text{A}$. If the voltmeter reading is $12\, \text{V}$,then the value of $R$ is ............ $\Omega$.

In the circuit shown,the readings of the ammeter and voltmeter are $4\,\, A$ and $20\,\, V$ respectively. The meters are non-ideal. Then $R$ is