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(B) The formula for resistance at temperature $T$ is $R_T = R_0[1 + \alpha(T - T_0)]$.Given: $\alpha = 0.00125\,^{\circ}C^{-1}$,$R_1 = 1\,\Omega$ at $

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$1100$

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(B) The formula for resistance at temperature $T$ is $R_T = R_0[1 + \alpha(T - T_0)]$.Given: $\alpha = 0.00125\,^{\circ}C^{-1}$,$R_1 = 1\,\Omega$ at $T_1 = 300\,K$ $(27\,^{\circ}C)$,and $R_2 = 2\,\Omega$ at $T_2 = ?$.Using the relation $R_2 = R_1[1 + \alpha(t_2 - t_1)]$,where $t_1 = 27\,^{\circ}C$:$2 = 1[1 + 0.00125(t_2 - 27)]$$2 - 1 = 0.00125(t_2 - 27)$$1 = 0.00125(t_2 - 27)$$t_2 - 27 = \frac{1}{0.00125} = 800$$t_2 = 800 + 27 = 827\,^{\circ}C$.Converting to Kelvin: $T_2 = 827 + 273 = 1100\,K$.

The temperature coefficient of resistance of a resistor wire is $0.00125\,^{\circ}C^{-1}$. At $300\,K$,its resistance is $1\,\Omega$. At what temperature in $K$ will its resistance be $2\,\Omega$?

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