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(A) Consider a point $A$ on the circle. The electron passes through this point in every revolution. The number of revolutions per second made by the e

Vedclass · Accepted Answer

$1 	imes 10^{-12} \, A$

Vedclass · Answer

(A) Consider a point $A$ on the circle. The electron passes through this point in every revolution. The number of revolutions per second made by the electron is given by the frequency $f$.$f = \frac{v}{2\pi r} = \frac{4 	imes 10^6}{2\pi 	imes 10 	imes 10^{-2}} = \frac{2}{\pi} 	imes 10^7 \, 	ext{rev/sec}$.The electric current $I$ is defined as the charge passing through a point per unit time:$I = \frac{q}{t} = f 	imes e$$I = \left( \frac{2}{\pi} 	imes 10^7 ight) 	imes (1.6 	imes 10^{-19}) \, A$$I = \frac{3.2}{\pi} 	imes 10^{-12} \, A$Since $\pi \approx 3.14$,we get $I \approx 1.019 	imes 10^{-12} \, A \approx 1 	imes 10^{-12} \, A$.

An electron moves with a constant speed of $4 \times 10^6 \, m/s$ in a circle of radius $10 \, cm$. Find the electric current at any point on the circle.

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