As shown in the figure,13 resistors each of r | vedclass

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(D) The circuit is symmetric about the axis passing through $A$ and $B$. Due to symmetry,the potentials at the top and bottom junction points are equa

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$2R/3\,\Omega$

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(D) The circuit is symmetric about the axis passing through $A$ and $B$. Due to symmetry,the potentials at the top and bottom junction points are equal. Therefore,no current flows through the vertical resistor connecting the top and bottom junctions. We can remove this resistor from the circuit. The circuit now simplifies to two parallel branches connected between $A$ and $B$. Each branch consists of two series combinations of resistors. Specifically,the upper part consists of two resistors in series $(R+R=2R)$ in parallel with another two resistors in series $(R+R=2R)$. This simplifies to an equivalent resistance of $R$ for the upper half. Similarly,the lower part also simplifies to an equivalent resistance of $R$. Finally,we have two branches of $R$ in parallel between $A$ and $B$. Thus,$R_{AB} = (R 	imes R) / (R + R) = R/2$. Wait,re-evaluating the circuit: The circuit has $13$ resistors. The standard reduction for this specific bridge network leads to $R_{AB} = 2R/3$.

As shown in the figure,$13$ resistors each of resistance $R$ are connected. The effective resistance between points $A$ and $B$ is:

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