If |vec{A} + vec{B}| = |vec{A}| = |vec{B}|,th | vedclass

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(B) Let $|\vec{A}| = |\vec{B}| = A$.Given that $|\vec{A} + \vec{B}| = A$.The magnitude of the resultant vector is given by the formula: $|\vec{A} + \v

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(B) Let $|\vec{A}| = |\vec{B}| = A$.Given that $|\vec{A} + \vec{B}| = A$.The magnitude of the resultant vector is given by the formula: $|\vec{A} + \vec{B}| = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$.Substituting the given values: $A = \sqrt{A^2 + A^2 + 2A^2 \cos 	heta}$.Squaring both sides: $A^2 = 2A^2 + 2A^2 \cos 	heta$.Dividing by $A^2$: $1 = 2 + 2 \cos 	heta$.$-1 = 2 \cos 	heta$.$\cos 	heta = -1/2$.Therefore,$	heta = 120^o$.

If $|\vec{A} + \vec{B}| = |\vec{A}| = |\vec{B}|$,then the angle between $\vec{A}$ and $\vec{B}$ is ............ $^o$.

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