(B) The distance of the $n^{th}$ bright fringe from the central maximum is given by the formula: $x_n = \frac{n D \lambda}{d}$ Given values: $n = 3$ $

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(B) The distance of the $n^{th}$ bright fringe from the central maximum is given by the formula: $x_n = \frac{n D \lambda}{d}$ Given values: $n = 3$ $D = 120 \, cm = 1.2 \, m$ $\lambda = 6500 \, \mathring A = 6500 \times 10^{-10} \, m$ $d = 2 \, mm = 2 \times 10^{-3} \, m$ Substituting these values into the formula: $x_3 = \frac{3 \times 1.2 \times 6500 \times 10^{-10}}{2 \times 10^{-3}}$ $x_3 = \frac{3 \times 1.2 \times 6.5 \times 10^{-7}}{2 \times 10^{-3}}$ $x_3 = 1.17 \times 10^{-3} \, m$ $x_3 = 1.17 \, mm$

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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In a Young's double-slit experiment,the light beam consists of two wavelengths $6500 \, \mathring A$ and $5200 \, \mathring A$. The distance between the slits is $2 \, mm$ and the distance between the plane of the slits and the screen is $120 \, cm$. Find the distance of the third bright fringe from the central maximum for the wavelength $6500 \, \mathring A$ in $mm$.

A
$0.19$
B
$1.17$
C
$1.98$
D
$2.15$

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Wave Optics

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Young's Double Slit Experiment (YDSE)

$A$ double slit experiment is immersed in water of refractive index $n = 1.33$. The slit separation is $d = 1 \text{ mm}$, and the distance between the slit and the screen is $D = 1.33 \text{ m}$. The slits are illuminated by light of wavelength $\lambda_0 = 6300 \text{ Å}$ in vacuum. The fringe width is:

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$A$ fringe width of $6 \ mm$ was produced for two slits separated by $1 \ mm$ apart. The screen is placed $10 \ m$ away. The wavelength of light used is $'x' \ nm$. The value of $'x'$ to the nearest integer is

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In a $YDSE$,light of two different wavelengths $(\lambda_1, \lambda_2)$ is incident normal to the plane of slits. The $n^{th}$ maxima of $\lambda_1$ coincides with the $m^{th}$ maxima of $\lambda_2$ exactly in front of one of the slits. Given $D = 1.5 \ m$,$d = 3 \ mm$,and $4500 \ \mathring{A} < \lambda_1, \lambda_2 < 7000 \ \mathring{A}$,then $n, m$ and $\lambda_1$ are:

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In a certain double-slit experimental arrangement,interference fringes of width $1.0 \ mm$ each are observed when light of wavelength $5000 \ \mathring{A}$ is used. Keeping the setup unaltered,if the source is replaced by another source of wavelength $6000 \ \mathring{A}$,the fringe width will be $...... \ mm$.

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The maximum intensity of fringes in Young's experiment is $I$. If one of the slits is closed,then the intensity at that place becomes $I_o$. Which of the following relations is true?

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$A$ fringe width of $6 \ mm$ was produced for two slits separated by $1 \ mm$ apart. The screen is placed $10 \ m$ away. The wavelength of light used is $'x' \ nm$. The value of $'x'$ to the nearest integer is

The maximum intensity of fringes in Young's experiment is $I$. If one of the slits is closed,then the intensity at that place becomes $I_o$. Which of the following relations is true?

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