Two plane mirrors A and B are placed parallel | vedclass

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(B) Let the distance between the two mirrors be $h = 0.2 \ m$ and the length of the mirrors be $L = 2\sqrt{3} \ m$. The angle of incidence is $i = 30^

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(B) Let the distance between the two mirrors be $h = 0.2 \ m$ and the length of the mirrors be $L = 2\sqrt{3} \ m$. The angle of incidence is $i = 30^o$.When the ray reflects,the horizontal distance $d$ covered between two consecutive reflections on the same mirror is given by $d = 2h 	an(i)$.Substituting the values: $d = 2 	imes 0.2 	imes 	an(30^o) = 0.4 	imes \frac{1}{\sqrt{3}} = \frac{0.4}{\sqrt{3}} \ m$.The total number of reflections $n$ is given by the ratio of the total length $L$ to the horizontal distance $d$ covered per reflection: $n = \frac{L}{d}$.$n = \frac{2\sqrt{3}}{0.4/\sqrt{3}} = \frac{2 	imes 3}{0.4} = \frac{6}{0.4} = 15$.Since the ray reflects from both mirrors,the total number of reflections is $2n = 2 	imes 15 = 30$.

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