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(B) The fringe width in $Y.D.S.E.$ is given by $\beta = \frac{\lambda D}{d}$.When the experiment is performed in a medium with refractive index $\mu$,

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decrease.

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(B) The fringe width in $Y.D.S.E.$ is given by $\beta = \frac{\lambda D}{d}$.When the experiment is performed in a medium with refractive index $\mu$,the wavelength of light changes to $\lambda' = \frac{\lambda}{\mu}$.Therefore,the new fringe width $\beta'$ becomes $\beta' = \frac{\lambda' D}{d} = \frac{\lambda D}{\mu d} = \frac{\beta}{\mu}$.Since the refractive index of water $\mu > 1$,the fringe width $\beta'$ will be less than the fringe width in air $\beta$.Thus,the fringe width decreases.

In Young's double-slit experiment,if the experiment is performed in air and then in water,the fringe width will ...

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