The diffraction of light starts from an obstacle (edge). It depends on ...

  • A
    Size of the obstacle (edge)
  • B
    Size of the obstacle (edge) and wavelength
  • C
    Distance of the screen from the obstacle (edge) and wavelength
  • D
    Size of the obstacle and its distance from the screen

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Similar Questions

For Bragg's diffraction by a crystal to occur,the $X$-ray of wavelength $\lambda$ and interatomic distance $d$ must satisfy which condition?

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$A$ screen is placed $0.5 \,m$ away from a single slit which is illuminated by a monochromatic light of wavelength $6000 \text{ Å}$. If the distance between the first and third minima in the diffraction pattern on the screen is $3 \,mm$, then the slit width is: (in $\,mm$)

$A$ diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light,then:

Light of wavelength $\lambda$ is incident on a single slit of width $a$,and the distance between the slit and the screen is $D$. In the diffraction pattern,if the slit width is equal to the width of the central maximum,then $D=$

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