For a light of wavelength 5000 , mathring{A} | vedclass

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(D) The condition for obtaining the $m^{	ext{th}}$ order diffraction minima is given by $a \sin 	heta = m \lambda$,where $a$ is the slit width,$	he

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$10 	imes 10^{-5} \, 	ext{cm}$

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(D) The condition for obtaining the $m^{	ext{th}}$ order diffraction minima is given by $a \sin 	heta = m \lambda$,where $a$ is the slit width,$	heta$ is the angle of diffraction,and $\lambda$ is the wavelength of light.For the first diffraction minimum,$m = 1$.Substituting the given values: $\lambda = 5000 \, \mathring{A} = 5000 	imes 10^{-10} \, 	ext{m} = 5 	imes 10^{-7} \, 	ext{m}$ and $	heta = 30^\circ$.$a \sin(30^\circ) = 1 	imes (5 	imes 10^{-7} \, 	ext{m})$$a 	imes (1/2) = 5 	imes 10^{-7} \, 	ext{m}$$a = 10 	imes 10^{-7} \, 	ext{m} = 10 	imes 10^{-5} \, 	ext{cm}$.

For a light of wavelength $5000 \, \mathring{A}$ incident normally on a slit,the first diffraction minimum is formed at an angle of $\theta = 30^\circ$. The width of the slit is:

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