If the sum of three numbers in an arithmetic | vedclass

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Question

(A) Let the three numbers in arithmetic progression be $(a - d)$,$a$,and $(a + d)$.Given their sum is $33$:$(a - d) + a + (a + d) = 33$$3a = 33$$a = 1

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) Let the three numbers in arithmetic progression be $(a - d)$,$a$,and $(a + d)$.Given their sum is $33$:$(a - d) + a + (a + d) = 33$$3a = 33$$a = 11$Given their product is $792$:$(11 - d) 	imes 11 	imes (11 + d) = 792$$(11 - d)(11 + d) = \frac{792}{11}$$121 - d^2 = 72$$d^2 = 121 - 72$$d^2 = 49$$d = 7$ (taking the positive value for the sequence)The numbers are $(11 - 7)$,$11$,and $(11 + 7)$,which are $4$,$11$,and $18$.The smallest number is $4$.

If the sum of three numbers in an arithmetic progression is $33$ and their product is $792$,what is the smallest number among them?

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