In how many ways can 16 rupees be divided amo | vedclass

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(B) Let the amount received by the $4$ persons be $x_1, x_2, x_3, x_4$ respectively.We are given $x_1 + x_2 + x_3 + x_4 = 16$,where $x_i \ge 3$ for al

Vedclass · Accepted Answer

$35$

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(B) Let the amount received by the $4$ persons be $x_1, x_2, x_3, x_4$ respectively.We are given $x_1 + x_2 + x_3 + x_4 = 16$,where $x_i \ge 3$ for all $i \in \{1, 2, 3, 4\}$.Let $y_i = x_i - 3$. Then $y_i \ge 0$.Substituting $x_i = y_i + 3$ into the equation:$(y_1 + 3) + (y_2 + 3) + (y_3 + 3) + (y_4 + 3) = 16$$y_1 + y_2 + y_3 + y_4 + 12 = 16$$y_1 + y_2 + y_3 + y_4 = 4$The number of non-negative integer solutions is given by the formula $\binom{n+r-1}{r-1}$,where $n=4$ and $r=4$.Number of ways $= \binom{4+4-1}{4-1} = \binom{7}{3} = \frac{7 	imes 6 	imes 5}{3 	imes 2 	imes 1} = 35$.

In how many ways can $16$ rupees be divided among $4$ persons such that no person receives less than $3$ rupees?

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