In how many ways can $5$ boys and $5$ girls be seated around a circular table such that no two girls are together?

  • A
    $5! \times 5!$
  • B
    $5! \times 4!$
  • C
    $\frac{1}{2} (5!)^2$
  • D
    $\frac{1}{2} (5! \times 4!)$

Explore More

Similar Questions

The number of ways in which $6$ men and $5$ women can sit at a round table,if no two women sit together,is:

If $5$ red roses and $5$ white roses of different sizes are used in preparing a garland,the probability that red and white roses come alternately is

The number of ways in which $5$ boys and $3$ girls can be seated on a round table,if a particular boy $B_1$ and a particular girl $G_1$ never sit adjacent to each other,is

The number of ways in which $6$ boys and $4$ girls can be seated around a round table such that $2$ special boys and a special girl never sit together is

In how many ways can $5$ keys be arranged in a ring?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo