In how many ways can $6$ men and $5$ women be seated around a circular table if no two women are to be seated together?

  • A
    $6! \times 5!$
  • B
    $6! \times P(7, 5)$
  • C
    $5! \times P(6, 5)$
  • D
    $7! \times 5!$

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