If there are m parallel lines in each of the | vedclass

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(A) parallelogram is formed by selecting $2$ lines from one set of $m$ parallel lines and $2$ lines from another set of $m$ parallel lines.However,the

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$(\binom{m}{2})^2$

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(A) parallelogram is formed by selecting $2$ lines from one set of $m$ parallel lines and $2$ lines from another set of $m$ parallel lines.However,the question implies we are considering the grid formed by these lines. If there are $m$ lines in each set,the number of ways to choose $2$ lines from each set is $\binom{m}{2} 	imes \binom{m}{2} = (\binom{m}{2})^2$.If the question implies that the $m$ lines are the lines *between* the boundary lines,then the total number of lines would be $m+2$,leading to $(\binom{m+2}{2})^2$. Given the standard interpretation of such problems where $m$ is the total number of lines in each set,the answer is $(\binom{m}{2})^2$.

If there are $m$ parallel lines in each of the two sets of parallel lines that form a parallelogram,then the total number of parallelograms formed is:

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