In how many ways can $12$ balls be distributed between two friends such that one gets $8$ balls and the other gets $4$ balls?

  • A
    $\frac{12!}{8!4!}$
  • B
    $\frac{2!12!}{8!4!}$
  • C
    $\frac{12!}{8!4!2!}$
  • D
    None of these

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