If vec{A} = hat{i} - 2hat{j} - 3hat{k},vec{B} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,calculate the cross product $\vec{A} 	imes \vec{B}$:$\vec{A} 	imes \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 1 & -2 & -3 \

Vedclass · Accepted Answer

$5(-\hat{i} + 3\hat{j} + 4\hat{k})$

Vedclass · Answer

(A) First,calculate the cross product $\vec{A} 	imes \vec{B}$:$\vec{A} 	imes \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 1 & -2 & -3 \ 2 & 1 & -1 \end{vmatrix}$$= \hat{i}(2 - (-3)) - \hat{j}(-1 - (-6)) + \hat{k}(1 - (-4))$$= \hat{i}(5) - \hat{j}(5) + \hat{k}(5) = 5\hat{i} - 5\hat{j} + 5\hat{k}$Now,calculate $(\vec{A} 	imes \vec{B}) 	imes \vec{C}$:$(\vec{A} 	imes \vec{B}) 	imes \vec{C} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 5 & -5 & 5 \ 1 & 3 & -2 \end{vmatrix}$$= \hat{i}(10 - 15) - \hat{j}(-10 - 5) + \hat{k}(15 - (-5))$$= \hat{i}(-5) - \hat{j}(-15) + \hat{k}(20)$$= -5\hat{i} + 15\hat{j} + 20\hat{k}$$= 5(-\hat{i} + 3\hat{j} + 4\hat{k})$

If $\vec{A} = \hat{i} - 2\hat{j} - 3\hat{k}$,$\vec{B} = 2\hat{i} + \hat{j} - \hat{k}$,and $\vec{C} = \hat{i} + 3\hat{j} - 2\hat{k}$,then $(\vec{A} \times \vec{B}) \times \vec{C} = \dots$

Similar Questions

If $u = i \times (a \times i) + j \times (a \times j) + k \times (a \times k),$ then

If $a=(1,2,3), b=(2,-1,1), c=(3,2,1)$ and $a \times(b \times c)=\alpha a+\beta b+\gamma c$,then

The vectors $\vec{a}$ and $\vec{b}$ are not perpendicular and $\vec{c}$ and $\vec{d}$ are two vectors satisfying $\vec{b} \times \vec{c} = \vec{b} \times \vec{d}$ and $\vec{a} \cdot \vec{d} = 0$. Then the vector $\vec{d}$ is equal to:

Let $\vec{v}$ be a vector such that $\vec{v} \times ((\hat{i}-\hat{k}) \times ((3\hat{i}+4\hat{j}) \times (\hat{j}+\hat{k}))) = \vec{0}$. Suppose $\vec{v} \cdot \hat{j} = -7$. Then $\vec{v} \cdot \hat{i}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module