Statement (A): In Delta ABC,overline{AB} + ov | vedclass

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(A) According to the Triangle Law of Vector Addition,for any triangle $ABC$,the sum of vectors along the sides in order is zero.$\overline{AB} + \over

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$A$ and $R$ are both independently true and $R$ is the correct explanation for $A$.

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(A) According to the Triangle Law of Vector Addition,for any triangle $ABC$,the sum of vectors along the sides in order is zero.$\overline{AB} + \overline{BC} + \overline{CA} = (\overline{AB} + \overline{BC}) + \overline{CA}$Using the triangle law,$\overline{AB} + \overline{BC} = \overline{AC}$.So,$\overline{AC} + \overline{CA} = \overline{AC} - \overline{AC} = 0$.Thus,Statement $(A)$ is true.Reason $(R)$ states that if $\overline{AB} = \vec{a}$ and $\overline{BC} = \vec{b}$,then $\overline{AC} = \vec{a} + \vec{b}$. This is the correct statement of the Triangle Law of Addition.Since the sum $\overline{AB} + \overline{BC} + \overline{CA} = 0$ is derived directly from the triangle law $\overline{AB} + \overline{BC} = \overline{AC}$,Reason $(R)$ is the correct explanation for Statement $(A)$.

Statement $(A):$ In $\Delta ABC$,$\overline{AB} + \overline{BC} + \overline{CA} = 0$.
Reason $(R):$ If $\overline{AB} = \vec{a}$ and $\overline{BC} = \vec{b}$,then $\overline{AC} = \vec{a} + \vec{b}$ (Triangle Law of Addition).

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Statement $(A):$ In $\Delta ABC$,$\overline{AB} + \overline{BC} + \overline{CA} = 0$.Reason $(R):$ If $\overline{AB} = \vec{a}$ and $\overline{BC} = \vec{b}$,then $\overline{AC} = \vec{a} + \vec{b}$ (Triangle Law of Addition).