What is the statement (p rightarrow sim p) we | vedclass

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(B) We know that $p \rightarrow q \equiv \sim p \vee q$. Applying this to the given expression: $(p$ $\rightarrow \sim p) \wedge (\sim p$ $\rightarrow

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Contradiction

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(B) We know that $p \rightarrow q \equiv \sim p \vee q$. Applying this to the given expression: $(p$ $\rightarrow \sim p) \wedge (\sim p$ $\rightarrow p) \equiv (\sim p \vee \sim p) \wedge (p \vee p)$. Using the idempotent law $(p \vee p \equiv p)$: $\equiv (\sim p) \wedge (p)$. Since $p \wedge \sim p \equiv c$ (where $c$ is a contradiction),the statement is a contradiction.

What is the statement $(p$ $\rightarrow \sim p) \wedge (\sim p$ $\rightarrow p)$?

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