What is the product of the roots of the equation $(x - 2)^2 - 3(x - 2) + 2 = 0$?

Let $x_1, x_2, x_3 \in \mathbb{R} \setminus \{0\}$,$x_1 + x_2 + x_3 \neq 0$ and $\frac{1}{x_1} + \frac{1}{x_2} + \frac{1}{x_3} = \frac{1}{x_1 + x_2 + x_3}$. Then $\frac{1}{x_1^n + x_2^n + x_3^n} = \frac{1}{x_1^n} + \frac{1}{x_2^n} + \frac{1}{x_3^n}$ holds good for:

Sum of all the roots of the equation $||2x-3|-4|=2$ is

If $|{x^2} - x - 6| = x + 2$,then the values of $x$ are

If $(x^2+5x+5)^{x+5}=1$,then the number of integers satisfying this equation is

The number of real roots of the equation $e^{4x} - e^{3x} - 4e^{2x} - e^{x} + 1 = 0$ is equal to $.....$