(A) Given the equation: $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$.Adding $\frac{2}{x - 1}$ to both sides,we get $x = 1$.However,for the original equ

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(A) Given the equation: $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$.Adding $\frac{2}{x - 1}$ to both sides,we get $x = 1$.However,for the original equation to be defined,the denominator $x - 1$ must not be zero,which implies $x \neq 1$.Since the only potential solution $x = 1$ is excluded from the domain,the equation has no roots.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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How many roots does the equation $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$ have?

A
No roots
B
One root
C
Two equal roots
D
Infinitely many roots

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4-2.Quadratic Equations and Inequations

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Solution of quadratic equations and Nature of roots

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How many roots does the equation $x - \frac{2}{x - 1} = 1 - \frac{2}{x - 1}$ have?

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