If the equation 2x^2 - kx + x + 8 = 0 has equ | vedclass

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(D) The given equation is $2x^2 - (k - 1)x + 8 = 0$.For equal and real roots,the discriminant $D = b^2 - 4ac$ must be equal to $0$.Here,$a = 2$,$b = -

Vedclass · Accepted Answer

$9$ and $-7$

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(D) The given equation is $2x^2 - (k - 1)x + 8 = 0$.For equal and real roots,the discriminant $D = b^2 - 4ac$ must be equal to $0$.Here,$a = 2$,$b = -(k - 1)$,and $c = 8$.Substituting these values into $D = 0$:$(-(k - 1))^2 - 4(2)(8) = 0$$(k - 1)^2 - 64 = 0$$(k - 1)^2 = 64$Taking the square root on both sides:$k - 1 = \pm 8$Case $1$: $k - 1 = 8 \Rightarrow k = 9$Case $2$: $k - 1 = -8 \Rightarrow k = -7$Therefore,the values of $k$ are $9$ and $-7$.

If the equation $2x^2 - kx + x + 8 = 0$ has equal and real roots,then the value of $k$ will be .....

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