Find the mean deviation about the mean for th | vedclass

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(B) First,calculate the mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.      $x_i$    $f_i$    $f_i x_i$    $|x_i - \bar{x}|$    $f_i |x_i - \bar{x}|$

Vedclass · Accepted Answer

$7.09$

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(B) First,calculate the mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.      $x_i$    $f_i$    $f_i x_i$    $|x_i - \bar{x}|$    $f_i |x_i - \bar{x}|$        $3$    $8$    $24$    $|3 - 15| = 12$    $96$        $9$    $10$    $90$    $|9 - 15| = 6$    $60$        $17$    $12$    $204$    $|17 - 15| = 2$    $24$        $23$    $9$    $207$    $|23 - 15| = 8$    $72$        $27$    $5$    $135$    $|27 - 15| = 12$    $60$        Total    $N = 44$    $\sum f_i x_i = 660$    -    $\sum f_i |x_i - \bar{x}| = 312$  Mean $\bar{x} = \frac{660}{44} = 15$.Mean deviation about mean $= \frac{\sum f_i |x_i - \bar{x}|}{N} = \frac{312}{44} \approx 7.09$.

$x_i$	$2$	$4$	$6$	$8$	$10$
$f_i$	$1$	$2$	$3$	$2$	$1$

Find the mean deviation about the mean for the following data:

$x_i$ $3$ $9$ $17$ $23$ $27$

$f_i$ $8$ $10$ $12$ $9$ $5$

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Find the mean deviation about the mean for the following data: $x_i$ $3$ $9$ $17$ $23$ $27$ $f_i$ $8$ $10$ $12$ $9$ $5$