The value of acceleration due to gravity is 9 | vedclass

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(C) We know that $1 \, m \approx 3.28084 \, ft$.To convert the acceleration due to gravity from $m/s^2$ to $ft/s^2$,we multiply the value by the conve

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$32$

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(C) We know that $1 \, m \approx 3.28084 \, ft$.To convert the acceleration due to gravity from $m/s^2$ to $ft/s^2$,we multiply the value by the conversion factor:$g = 9.8 \, m/s^2 	imes 3.28084 \, ft/m$$g \approx 32.14 \, ft/s^2$.Rounding to the nearest whole number,we get $g \approx 32 \, ft/s^2$.

The value of acceleration due to gravity is $9.8 \, m s^{-2}$. Its value in $ft/s^2$ is approximately:

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