(D) Given: Energy of each photon $E = 2.5 \ eV$, Work function $\Phi_0 = 4.5 \ eV$.According to Einstein's photoelectric equation, the photoelectric e

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Emission of electrons is not possible.

(D) Given: Energy of each photon $E = 2.5 \ eV$, Work function $\Phi_0 = 4.5 \ eV$.According to Einstein's photoelectric equation, the photoelectric effect occurs only if the energy of the incident photon is greater than or equal to the work function of the metal $(E \ge \Phi_0)$.Here, $E = 2.5 \ eV$ and $\Phi_0 = 4.5 \ eV$.Since $E Therefore, no photoelectric emission takes place, regardless of the number of photons incident.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

Easy

Two photons, each having an energy of $2.5 \ eV$, are incident on a metal surface with a work function of $4.5 \ eV$. Then . . . . . . .

A
The kinetic energy of the emitted electron is $0.5 \ eV$.
B
The kinetic energy of the emitted electron is $2 \ eV$.
C
The kinetic energy of the emitted electron ranges from $0$ to $0.5 \ eV$.
D
Emission of electrons is not possible.

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

Light of two different frequencies whose photons have energies $1 \text{ eV}$ and $2.5 \text{ eV}$ respectively,successively illuminate a metallic surface whose work function is $0.5 \text{ eV}$. The ratio of the maximum speeds of the emitted electrons will be:

EasyKCET 2015

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The difference between threshold wavelengths for two metal surfaces $A$ and $B$ having work functions $\phi_A = 9 \, eV$ and $\phi_B = 4.5 \, eV$ in $nm$ is: (Given,$hc = 1242 \, eV \, nm$)

EasyJEE MAIN 2023

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Light of frequency $v$ is incident on a certain photoelectric material with a threshold frequency $v_0$. What is the work function for the material?

Easy

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The maximum velocity of the photoelectrons emitted from the surface is $v$ when light of frequency $n$ falls on a metal surface. If the incident frequency is increased to $3n$,the maximum velocity of the ejected photoelectrons will be:

MediumJEE MAIN 2017

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The threshold wavelength of a metal surface is $5 \times 10^{-10} \, m$. When it is illuminated by light of wavelength $2 \times 10^{-10} \, m$,the stopping potential is $V_0$. What will be the stopping potential if the wavelength of the incident light is doubled?

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Two photons, each having an energy of $2.5 \ eV$, are incident on a metal surface with a work function of $4.5 \ eV$. Then . . . . . . .

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Light of two different frequencies whose photons have energies $1 \text{ eV}$ and $2.5 \text{ eV}$ respectively,successively illuminate a metallic surface whose work function is $0.5 \text{ eV}$. The ratio of the maximum speeds of the emitted electrons will be:

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