The work functions for tungsten and sodium ar | vedclass

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(C) The work function $\phi_0$ is related to the threshold wavelength $\lambda_0$ by the formula: $\phi_0 = \frac{hc}{\lambda_0}$.Since $h$ and $c$ ar

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$2791$

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(C) The work function $\phi_0$ is related to the threshold wavelength $\lambda_0$ by the formula: $\phi_0 = \frac{hc}{\lambda_0}$.Since $h$ and $c$ are constants,we have $\lambda_0 \propto \frac{1}{\phi_0}$.Therefore,$\frac{(\lambda_0)_{	ext{tungsten}}}{(\lambda_0)_{	ext{sodium}}} = \frac{(\phi_0)_{	ext{sodium}}}{(\phi_0)_{	ext{tungsten}}}$.Substituting the given values: $\frac{(\lambda_0)_{	ext{tungsten}}}{5460 \ \mathring{A}} = \frac{2.3 \ eV}{4.5 \ eV}$.$(\lambda_0)_{	ext{tungsten}} = 5460 	imes \frac{2.3}{4.5} \ \mathring{A}$.$(\lambda_0)_{	ext{tungsten}} \approx 2790.6 \ \mathring{A} \approx 2791 \ \mathring{A}$.

The work functions for tungsten and sodium are $4.5 \ eV$ and $2.3 \ eV$ respectively. If the threshold wavelength for sodium is $5460 \ \mathring{A}$,then the threshold wavelength for tungsten is .......... $\mathring{A}$.

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