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(C) Given: Mass $m = 200 \ g = 0.2 \ kg$. Speed $v = 5 \ m/hr = \frac{5}{3600} \ m/s$. Planck's constant $h = 6.626 	imes 10^{-34} \ J \cdot s$. The

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$10^{-30} \ m$

Vedclass · Answer

(C) Given: Mass $m = 200 \ g = 0.2 \ kg$. Speed $v = 5 \ m/hr = \frac{5}{3600} \ m/s$. Planck's constant $h = 6.626 	imes 10^{-34} \ J \cdot s$. The de Broglie wavelength $\lambda$ is given by the formula: $\lambda = \frac{h}{mv}$ Substituting the values: $\lambda = \frac{6.626 	imes 10^{-34}}{0.2 	imes (5/3600)}$ $\lambda = \frac{6.626 	imes 10^{-34} 	imes 3600}{0.2 	imes 5}$ $\lambda = \frac{23853.6 	imes 10^{-34}}{1}$ $\lambda \approx 2.385 	imes 10^{-30} \ m$. Thus,the order of magnitude is $10^{-30} \ m$.

An object of mass $200 \ g$ is moving with a speed of $5 \ m/hr$. The order of the de Broglie wavelength associated with it is ...... $(h = 6.626 \times 10^{-34} \ J \cdot s)$.

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