A 10 kW transmitter emits radio waves of wav | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Power $P = 10 \ kW = 10^4 \ W$,Wavelength $\lambda = 500 \ m$.Energy of one photon is $E = \frac{hc}{\lambda}$.The number of photons emitte

Vedclass · Accepted Answer

$10^{30}$

Vedclass · Answer

(B) Given: Power $P = 10 \ kW = 10^4 \ W$,Wavelength $\lambda = 500 \ m$.Energy of one photon is $E = \frac{hc}{\lambda}$.The number of photons emitted per second $n$ is given by $n = \frac{P}{E} = \frac{P \lambda}{hc}$.Substituting the values: $h = 6.63 	imes 10^{-34} \ J \cdot s$,$c = 3 	imes 10^8 \ m/s$.$n = \frac{10^4 	imes 500}{6.63 	imes 10^{-34} 	imes 3 	imes 10^8} = \frac{5 	imes 10^6}{19.89 	imes 10^{-26}} \approx 0.251 	imes 10^{32} = 2.51 	imes 10^{31}$.The order of magnitude is $10^{31}$,which is closest to $10^{30}$ among the given options.

Column $I$	Column $II$
$A$. Growth	$I$. Production of offspring.
$B$. Reproduction	$II$. Composed of one or more cells.
$C$. Metabolism	$III$. Increase in mass and increase in number of individuals.
$D$. Cellular organization	$IV$. Sum total of all chemical reactions occurring in the body.

$A$ $10 \ kW$ transmitter emits radio waves of wavelength $500 \ m$. The number of photons emitted per second by the transmitter is of the order of:

Similar Questions

Where is the Forest Research Institute $(FRI)$ located?

If the distance between the points $(a \cos \theta, a \sin \theta)$ and $(a \cos \phi, a \sin \phi)$ is $2a$,then $\theta$ is equal to

$A$ gas is filled in a cylinder. Its temperature is increased by $20\%$ on the Kelvin scale and its volume is reduced by $10\%$. How much percentage of the gas will leak out?

$\sum_{k=1}^{\infty} \frac{1}{k!}\left(\sum_{n=1}^k 2^{n-1}\right)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module