The momentum of a photon with frequency 1.5 t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The momentum $p$ of a photon is given by the relation $p = \frac{h}{\lambda}$.Since the speed of light $c = f \lambda$,we have $\lambda = \frac{c}

Vedclass · Accepted Answer

$3.3 	imes 10^{-29} \ kg \ m/s$

Vedclass · Answer

(A) The momentum $p$ of a photon is given by the relation $p = \frac{h}{\lambda}$.Since the speed of light $c = f \lambda$,we have $\lambda = \frac{c}{f}$.Substituting this into the momentum formula,we get $p = \frac{hf}{c}$.Given: $h = 6.63 	imes 10^{-34} \ J \ s$,$f = 1.5 	imes 10^{13} \ Hz$,and $c = 3 	imes 10^8 \ m/s$.$p = \frac{6.63 	imes 10^{-34} 	imes 1.5 	imes 10^{13}}{3 	imes 10^8}$.$p = \frac{9.945 	imes 10^{-21}}{3 	imes 10^8} \approx 3.315 	imes 10^{-29} \ kg \ m/s$.Rounding to the given options,the correct value is $3.3 	imes 10^{-29} \ kg \ m/s$.

The momentum of a photon with frequency $1.5 \times 10^{13} \ Hz$ is .......

Similar Questions

If the momentum of a photon is $p$,then its frequency is ........

The rest energy of an electron is $0.511 \, MeV$. The electron is accelerated from rest to a velocity $0.5 \, c$. The change in its energy will be ............ $MeV$.

$A$ $200\, W$ sodium street lamp emits yellow light of wavelength $0.6\, \mu m$. Assuming it to be $25\%$ efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is:

The energy of a photon of visible light with the maximum wavelength in $eV$ is approximately .......

Write the equation for the effective mass of a photon.

Vedclass Test Series

Exam Paper Generator

Online Exam Module