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(A) The minimum wavelength $(\lambda_{\min})$ of $X$-rays is given by the formula: $\lambda_{\min} = \frac{hc}{eV} = \frac{12375}{V(	ext{in volts})}

Vedclass · Accepted Answer

$0.31$

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(A) The minimum wavelength $(\lambda_{\min})$ of $X$-rays is given by the formula: $\lambda_{\min} = \frac{hc}{eV} = \frac{12375}{V(	ext{in volts})} \mathring A$.Given the operating voltage $V = 40 \ kV = 40,000 \ V$.Substituting the value: $\lambda_{\min} = \frac{12375}{40000} \mathring A$.$\lambda_{\min} = 0.309375 \mathring A \approx 0.31 \mathring A$.

The minimum wavelength of $X$-rays produced in a Coolidge tube operating at $40 \ kV$ is ..... $\mathring A$.

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