At temperature t , ^oC,the pressure exerted b | vedclass

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(A) Using the ideal gas equation $PV = nRT$,where $P = 1 \, atm$,$n = \frac{12}{120} = 0.1 \, mol$,and $T = (273 + t) \, K$.$1 	imes V = 0.1 	imes R

Vedclass · Accepted Answer

$0.82$

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(A) Using the ideal gas equation $PV = nRT$,where $P = 1 \, atm$,$n = \frac{12}{120} = 0.1 \, mol$,and $T = (273 + t) \, K$.$1 	imes V = 0.1 	imes R 	imes (273 + t)$ ...... $(1)$After increasing the temperature by $10 \, ^oC$:$P' = 1 + 0.1 = 1.1 \, atm$,$T' = (273 + t + 10) = (283 + t) \, K$.$1.1 	imes V = 0.1 	imes R 	imes (283 + t)$ ...... $(2)$Dividing $(1)$ by $(2)$:$\frac{1}{1.1} = \frac{273 + t}{283 + t}$$283 + t = 1.1 	imes (273 + t)$$283 + t = 300.3 + 1.1t$$0.1t = -17.3 \implies t = -173 \, ^oC$.Substituting $t$ in $(1)$ with $R = 0.082 \, L \cdot atm \cdot K^{-1} \cdot mol^{-1}$:$V = 0.1 	imes 0.082 	imes (273 - 173) = 0.1 	imes 0.082 	imes 100 = 0.82 \, L$.

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