If the value of u_{rms} at 27,^{circ}C is 30s | vedclass

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(D) We know that the root mean square velocity is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$.Given: $T = 27\,^{\circ}C = 27 + 273 = 300\,K

Vedclass · Accepted Answer

$0.001$

Vedclass · Answer

(D) We know that the root mean square velocity is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$.Given: $T = 27\,^{\circ}C = 27 + 273 = 300\,K$ and $u_{rms} = 30\sqrt{R}$.Substituting the values: $30\sqrt{R} = \sqrt{\frac{3 	imes R 	imes 300}{M}}$.Squaring both sides: $900R = \frac{900R}{M}$.Therefore,$M = 1\,g$.Converting to kilograms: $M = \frac{1}{1000}\,kg = 0.001\,kg$.

If the value of $u_{rms}$ at $27\,^{\circ}C$ is $30\sqrt{R}$,what is the molar mass of the gas in kilograms?

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