In the reaction Cr_2O_7^{2-} + X xrightarrow{ | vedclass

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Question

(B) The reaction involves the reduction of dichromate $(Cr_2O_7^{2-})$ to $Cr^{3+}$,which means $X$ must act as a reducing agent and undergo oxidation

Vedclass · Accepted Answer

$SO_4^{2-}$

Vedclass · Answer

(B) The reaction involves the reduction of dichromate $(Cr_2O_7^{2-})$ to $Cr^{3+}$,which means $X$ must act as a reducing agent and undergo oxidation.In $SO_4^{2-}$,the oxidation state of sulfur is $+6$,which is its maximum oxidation state.Therefore,$SO_4^{2-}$ cannot be oxidized further and cannot act as a reducing agent in this reaction.Thus,$SO_4^{2-}$ cannot be $X$.

In the reaction $Cr_2O_7^{2-} + X \xrightarrow{H^+} Cr^{3+} + H_2O + \text{Oxidized product of } X$,which of the following cannot be $X$?

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