Assertion: The average oxidation number of su | vedclass

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(C) The structure of sodium tetrathionate $(Na_2S_4O_6)$ is $Na^+[O_3S-S-S-SO_3]^-Na^+$.In this structure,the two terminal sulfur atoms have an oxidat

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Assertion is true,but the reason is false.

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(C) The structure of sodium tetrathionate $(Na_2S_4O_6)$ is $Na^+[O_3S-S-S-SO_3]^-Na^+$.In this structure,the two terminal sulfur atoms have an oxidation state of $+5$,while the two central sulfur atoms have an oxidation state of $0$.The average oxidation number is calculated as $\frac{5 + 0 + 0 + 5}{4} = \frac{10}{4} = 2.5$.The reason is false because the two central sulfur atoms are not directly bonded to oxygen atoms,but the assertion is true.

Assertion: The average oxidation number of sulfur in $Na_2S_4O_6$ is $2.5$.
Reason: Two $S$ atoms are not directly bonded to $O$-atoms.

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Assertion: The average oxidation number of sulfur in $Na_2S_4O_6$ is $2.5$.Reason: Two $S$ atoms are not directly bonded to $O$-atoms.