Which of the following orders of ionization energy is correct?

  • A
    $Be > B > C > N > O$
  • B
    $B < Be < C < O < N$
  • C
    $B < Be < C < N < O$
  • D
    $B < Be < N < C < O$

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Similar Questions

Ionization energy increases in the order

The first three ionisation energies (in $kJ/mol$) of three representative elements are given below:
Element $IE_1$ $IE_2$ $IE_3$
$P$ $495.8$ $4562$ $6910$
$Q$ $737.7$ $1451$ $7733$
$R$ $577.5$ $1817$ $2745$

Which of the following options is incorrect?

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Which of the following electronic configurations represents the atom with the lowest first ionization enthalpy?

For one of the elements,various successive ionization enthalpies (in $kJ \cdot mol^{-1}$) are given below:
$I.E.$ $1^{st}$ $2^{nd}$ $3^{rd}$ $4^{th}$ $5^{th}$
Value $577.5$ $1810$ $2750$ $11580$ $14820$

The element is:

Among the second period elements,the actual ionization enthalpies are in the order $Li < B < Be < C < O < N < F < Ne$. Explain why:
$(i)$ $Be$ has higher $\Delta_{i}H$ than $B$
$(ii)$ $O$ has lower $\Delta_{i}H$ than $N$ and $F$?

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