What is the correct order of radii for F, F^- | vedclass

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(D) The species $O^{2-}$ and $F^-$ are isoelectronic,having $10$ electrons each. For isoelectronic species,the ionic radius decreases as the nuclear c

Vedclass · Accepted Answer

$O^{2-} > F^- > O > F$

Vedclass · Answer

(D) The species $O^{2-}$ and $F^-$ are isoelectronic,having $10$ electrons each. For isoelectronic species,the ionic radius decreases as the nuclear charge $(Z)$ increases. Since $Z$ for $O$ is $8$ and $F$ is $9$,the order is $O^{2-} > F^-$.Comparing neutral atoms,the atomic radius decreases across a period from left to right. Thus,$O > F$.Furthermore,an anion is always larger than its parent neutral atom because of increased electron-electron repulsion and decreased effective nuclear charge per electron. Therefore,$O^{2-} > O$ and $F^- > F$.Combining these,the overall order of radii is $O^{2-} > F^- > O > F$.

What is the correct order of radii for $F, F^-, O,$ and $O^{2-}$?

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