Which of the following is the correct increas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The ionic radius increases down a group and decreases across a period from left to right.For the given elements,$Mg$ ($2^{nd}$ group,$3^{rd}$ peri

Vedclass · Accepted Answer

$Mg < Na < K < Rb$

Vedclass · Answer

(D) The ionic radius increases down a group and decreases across a period from left to right.For the given elements,$Mg$ ($2^{nd}$ group,$3^{rd}$ period) has the smallest size.$Na$ ($1^{st}$ group,$3^{rd}$ period) is larger than $Mg$.$K$ ($1^{st}$ group,$4^{th}$ period) is larger than $Na$.$Rb$ ($1^{st}$ group,$5^{th}$ period) is the largest.Therefore,the increasing order of ionic radii is $Mg < Na < K < Rb$.

Which of the following is the correct increasing order of ionic radii for $Na, Rb, K,$ and $Mg$?

Similar Questions

In $Cl_2$, the van der Waals radius is $180 \ pm$. What is the distance between the two atoms (in $pm$)?

Explain the measurement methods of atomic radius.

The bond length in $Cl_2$ is $198 \ pm$. Calculate the atomic radius of chlorine. (in $pm$)

The ionic radii of $O^{2-}, F^{-}, Na^{+}$,and $Mg^{2+}$ are in the order :

$K^{+}$,$Cl^{-}$,$Ca^{2+}$,and $S^{2-}$ ions are isoelectronic. The decreasing order of their ionic radii is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module