When an aqueous solution of sodium sulfate (N | vedclass

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(D) During the electrolysis of an aqueous solution of $Na_2SO_4$ using inert electrodes,water undergoes electrolysis.At the cathode,the reduction of w

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$H_2, O_2$

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(D) During the electrolysis of an aqueous solution of $Na_2SO_4$ using inert electrodes,water undergoes electrolysis.At the cathode,the reduction of water occurs: $2H_2O(l) + 2e^- \rightarrow H_2(g) + 2OH^-(aq)$.At the anode,the oxidation of water occurs: $2H_2O(l) \rightarrow O_2(g) + 4H^+(aq) + 4e^-$.Therefore,the products obtained at the cathode and anode are $H_2$ and $O_2$,respectively.

When an aqueous solution of sodium sulfate $(Na_2SO_4)$ is electrolyzed,what are the products obtained at the cathode and anode,respectively?

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