A metal M readily forms a water-soluble sulfa | vedclass

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(A) The metal $Be$ forms $BeSO_4$ which is water-soluble. $Be(OH)_2$ is amphoteric and dissolves in $NaOH$ to form sodium beryllate. $Be(OH)_2 + 2NaOH

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$Be$

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(A) The metal $Be$ forms $BeSO_4$ which is water-soluble. $Be(OH)_2$ is amphoteric and dissolves in $NaOH$ to form sodium beryllate. $Be(OH)_2 + 2NaOH 	o Na_2BeO_2 + 2H_2O$. $BeO$ is known to become inert (less reactive) upon strong heating. Other alkaline earth metals like $Mg, Ca, Sr$ form hydroxides that are not soluble in $NaOH$ as they are basic in nature,whereas $Be(OH)_2$ is amphoteric.

$A$ metal $M$ readily forms a water-soluble sulfate $MSO_4$,a water-insoluble hydroxide $M(OH)_2$,and an oxide $MO$ which becomes inert upon heating. The hydroxide is soluble in $NaOH$. What is $M$?

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