(A) According to Kohlrausch's law,the limiting molar conductivity of a weak electrolyte like acetic acid $(HOAc)$ can be calculated from the limiting

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(A) According to Kohlrausch's law,the limiting molar conductivity of a weak electrolyte like acetic acid $(HOAc)$ can be calculated from the limiting molar conductivities of strong electrolytes:$\Lambda^{\infty}_{HOAc} = \Lambda^{\infty}_{NaOAc} + \Lambda^{\infty}_{HCl} - \Lambda^{\infty}_{NaCl}$Substituting the given values:$\Lambda^{\infty}_{HOAc} = 91.0 + 426.2 - 126.5$$\Lambda^{\infty}_{HOAc} = 517.2 - 126.5 = 390.7 \, S \, cm^{2} \, mol^{-1}$

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Medium

Given the limiting molar conductivities at $25^{\circ}C$ for the following electrolytes in $S \, cm^{2} \, mol^{-1}$:
$KCl = 149.9$
$KNO_{3} = 145.0$
$HCl = 426.2$
$NaOAc = 91.0$
$NaCl = 126.5$
Calculate $\Lambda^{\infty}_{HOAc}$ using the Kohlrausch law of independent migration of ions.

A
$390.7$
B
$217.5$
C
$517.2$
D
$552.7$

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Conductor and Conductance and Cell constant

At $25\,^{\circ}C$,the specific conductivity of a normal solution of $KCl$ is $0.002765\,S\,cm^{-1}$. The resistance of the cell is $400\,\Omega$. The cell constant is: (in $,cm^{-1}$)

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Given the limiting molar conductivities at $25^{\circ}C$ for the following electrolytes in $S \, cm^{2} \, mol^{-1}$:$KCl = 149.9$$KNO_{3} = 145.0$$HCl = 426.2$$NaOAc = 91.0$$NaCl = 126.5$Calculate $\Lambda^{\infty}_{HOAc}$ using the Kohlrausch law of independent migration of ions.

Similar Questions

At $25\,^{\circ}C$,the specific conductivity of a normal solution of $KCl$ is $0.002765\,S\,cm^{-1}$. The resistance of the cell is $400\,\Omega$. The cell constant is: (in $,cm^{-1}$)

The unit of cell constant is

The electrodes of a conductivity cell are $3 \text{ cm}$ apart and have a cross-sectional area of $4 \text{ cm}^2$. The cell constant of the cell (in $\text{cm}^{-1}$) is

What is the molar conductivity of $CH_3COOH$ at infinite dilution if the molar conductivities of $H_2SO_4$, $K_2SO_4$, and $CH_3COOK$ at infinite dilution are $x$, $y$, and $z$ $\Omega^{-1} \text{cm}^2 \text{mol}^{-1}$ respectively?

How can the ionic conductivity of an unknown solution be determined?

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Given the limiting molar conductivities at $25^{\circ}C$ for the following electrolytes in $S \, cm^{2} \, mol^{-1}$:
$KCl = 149.9$
$KNO_{3} = 145.0$
$HCl = 426.2$
$NaOAc = 91.0$
$NaCl = 126.5$
Calculate $\Lambda^{\infty}_{HOAc}$ using the Kohlrausch law of independent migration of ions.